-18 < х`4 - 9х'2 < 0 решить уравнение -18 < х`4 - 9х'2 < 0. Created by sansahaste. algebra-ru

+ + + + + (- 3) - - - - - (0) - - - - - (3) + + + + + /////////// //////////// + + + + + (-√6)- - - - - (-√3)+ + + + + (√3)- - - - - (√6)+ + + + + ///////////// ///////////// ///////////// (- 3)- - - - - - - - - - - - - - - - (0)- - - - - - - - - - - - - - - - - -(3)Ответ : x ∈ ( - 3 ; - √6) ∪ ( - √3 ; 0) ∪ (0 ; √3) ∪ (√6 ; 3)

-18 < х`4 - 9х'2 < 0 решить уравнение -18 < х`4

sansahaste @sansahaste

July 2022 1 8 Report

-18 < х`4 - 9х'2 < 0
решить уравнение

-18 < х`4 - 9х'2 < 0

Answers & Comments

Universalka

Verified answer

$\displaystyle\bf\\-18$

+ + + + + (- 3) - - - - - (0) - - - - - (3) + + + + +

/////////// ////////////

$\displaystyle\bf\\2)\\x^{4} -9x^{2} >-18\\\\x^{4}-9x^{2} +18>0\\\\(x^{2} -6)(x^{2} -3)>0\\\\(x-\sqrt{6} )(x+\sqrt{6} )(x-\sqrt{3} )(x+\sqrt{3} )>0$

+ + + + + (-√6)- - - - - (-√3)+ + + + + (√3)- - - - - (√6)+ + + + +

///////////// ///////////// /////////////

(- 3)- - - - - - - - - - - - - - - - (0)- - - - - - - - - - - - - - - - - -(3)

Ответ : x ∈ ( - 3 ; - √6) ∪ ( - √3 ; 0) ∪ (0 ; √3) ∪ (√6 ; 3)

2 votes Thanks 1

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