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fike129
@fike129
July 2022
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AnonimusPro
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1) (x+6)(2x-9-x)=0; x+6=0; x1=-6; x-9=0; x2=9;
2) (x-10)(3x+4-x+8)=0; (x-10)(2x+12)=0; x-10=0; x1=10; 2x=-12; x2=-6;
3)(3x+1)(3(3x+1)-4)=0; 3x=-1; x1=-1/3; 9x=1; x2=1/9;
4)(9x-12)(1-x)=0; 9x=12; x1=12/9=4/3; 1-x=0; x2=1
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Verified answer
1) (x+6)(2x-9-x)=0; x+6=0; x1=-6; x-9=0; x2=9;2) (x-10)(3x+4-x+8)=0; (x-10)(2x+12)=0; x-10=0; x1=10; 2x=-12; x2=-6;
3)(3x+1)(3(3x+1)-4)=0; 3x=-1; x1=-1/3; 9x=1; x2=1/9;
4)(9x-12)(1-x)=0; 9x=12; x1=12/9=4/3; 1-x=0; x2=1