[tex]N(MgO) = 1,806*10^{23}\\\\Na = 6,02*10^{23}\\\\n = \frac{N}{Na} \\\\m = M*n\\\\M(MgO) = 24 + 16 = 40 g/mol\\\\n(MgO) =\frac{1,806*10^{23}}{6,02*10^{23}} = 0,3 mol\\\\m(MgO) = 0,3 * 40 = 12 g[/tex]
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[tex]N(MgO) = 1,806*10^{23}\\\\Na = 6,02*10^{23}\\\\n = \frac{N}{Na} \\\\m = M*n\\\\M(MgO) = 24 + 16 = 40 g/mol\\\\n(MgO) =\frac{1,806*10^{23}}{6,02*10^{23}} = 0,3 mol\\\\m(MgO) = 0,3 * 40 = 12 g[/tex]