Ответ:
[tex](b+6)(b-6)-b(b+8)=b^{2} -6b+6b-36-b^{2} -8b=b^{2} -b^{2} -6b+6b-8b-36= -8b-36[/tex]
Если [tex]b= -\frac{1}{8}[/tex] , то [tex]-8*(-\frac{1}{8})-36=\frac{8*1}{8} -36=1-36=-35[/tex]
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Ответ:
[tex](b+6)(b-6)-b(b+8)=b^{2} -6b+6b-36-b^{2} -8b=b^{2} -b^{2} -6b+6b-8b-36= -8b-36[/tex]
Если [tex]b= -\frac{1}{8}[/tex] , то [tex]-8*(-\frac{1}{8})-36=\frac{8*1}{8} -36=1-36=-35[/tex]