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antonanton9914
@antonanton9914
September 2021
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19. задание решите уравнение 3cos^2...
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sedinalana
Verified answer
Делим на cos²x
3-tg²x-2tgx=0
tg²x+2tgx-3=0
tgx=a
a²+2a-3=0
a1+a2=-2 U a1*a2=-3
a1=-3⇒tgx=-3⇒x=-arctg3+πn,n∈z
a2=1⇒tgx=1⇒x=π/4+πk,k∈z
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Answers & Comments
Verified answer
Делим на cos²x3-tg²x-2tgx=0
tg²x+2tgx-3=0
tgx=a
a²+2a-3=0
a1+a2=-2 U a1*a2=-3
a1=-3⇒tgx=-3⇒x=-arctg3+πn,n∈z
a2=1⇒tgx=1⇒x=π/4+πk,k∈z