Ответ:
на фототооооооооооооооооооооооо
[tex]x \neq4 \: \: \:and \: \: \: x \neq \frac{1}{3} \\ \frac{x + 1}{x - 4} = \frac{3x + 1}{3x - 1} \\ (3x - 1)(x + 1 )= (x - 4)(3x + 1) \\ 3 {x}^{2} + 3x - x - 1 = 3 {x}^{2} + x - 12x - 4 \\ 3 {x}^{2} - 3 {x}^{2} + 2x + 11x = - 4 + 1 \\ 13x = - 3 \\ x = - \frac{3}{13} [/tex]
Ответ: х = - 3/13
[tex]x\neq \frac{2}{3} \: \: \: and \: \: \: x\neq1.5 \\ \frac{9x - 7}{3x - 2} - \frac{4x - 5}{2x - 3} = 1 \\ \frac{9x - 7}{3x - 2} - \frac{4x - 5}{2x - 3} - 1 = 0 \\ \frac{(9x - 7)(2x - 3) - (4x - 5)(3x - 2) - (3x - 2)(2x - 3)}{(3x - 2)(2x - 3)} = 0 \\ 18 {x}^{2} - 27x - 14x + 21 - 12 {x}^{2} + 8x + 15x - 10 - 6 {x}^{2} + 9x + 4x - 6 = 0 \\ - 5x + 5 = 0 \\ 5x = 5 \\ x = 5 \div 5 \\ x = 1[/tex]
Ответ: х = 1
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Ответ:
на фототооооооооооооооооооооооо
5)
[tex]x \neq4 \: \: \:and \: \: \: x \neq \frac{1}{3} \\ \frac{x + 1}{x - 4} = \frac{3x + 1}{3x - 1} \\ (3x - 1)(x + 1 )= (x - 4)(3x + 1) \\ 3 {x}^{2} + 3x - x - 1 = 3 {x}^{2} + x - 12x - 4 \\ 3 {x}^{2} - 3 {x}^{2} + 2x + 11x = - 4 + 1 \\ 13x = - 3 \\ x = - \frac{3}{13} [/tex]
Ответ: х = - 3/13
6)
[tex]x\neq \frac{2}{3} \: \: \: and \: \: \: x\neq1.5 \\ \frac{9x - 7}{3x - 2} - \frac{4x - 5}{2x - 3} = 1 \\ \frac{9x - 7}{3x - 2} - \frac{4x - 5}{2x - 3} - 1 = 0 \\ \frac{(9x - 7)(2x - 3) - (4x - 5)(3x - 2) - (3x - 2)(2x - 3)}{(3x - 2)(2x - 3)} = 0 \\ 18 {x}^{2} - 27x - 14x + 21 - 12 {x}^{2} + 8x + 15x - 10 - 6 {x}^{2} + 9x + 4x - 6 = 0 \\ - 5x + 5 = 0 \\ 5x = 5 \\ x = 5 \div 5 \\ x = 1[/tex]
Ответ: х = 1