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sewonhan
@sewonhan
August 2021
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Упростите выражение (1+sin4a-cos4a)/(1+cos4a+sin4a)
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Vas61
(cos²2α+sin²2α+2sin2αcos2α-cos²2α+sin²2α)/(cos²2α+sin²2α+cos²2α-sin²2α+2sin2αcos2α)=(2sin²2α+2sin2αcos2α)/(2cos²2α+2sin2αcos2α)=
2sin2α(sin2α+cos2α)/2cos2α(cos2α+sin2α)=sin2α/cos2α=tg2α
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Answers & Comments
2sin2α(sin2α+cos2α)/2cos2α(cos2α+sin2α)=sin2α/cos2α=tg2α