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oreaann
@oreaann
July 2022
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Помогите преобразовать тригонометрическое выражение:
ctgα+(sinα/(1+cosα))
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m11m
Verified answer
[cosα/sinα] + [sinα/(1+cosα)]=[cosα(1+cosα)+sin²α]/[sinα(1+cosα)]=
=[cosα+cos²α+sin²α] / [sinα(1+cosα)] = [cosα+1] / [sinα(1+cosα)]=
=1/sinα
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oreaann
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Answers & Comments
Verified answer
[cosα/sinα] + [sinα/(1+cosα)]=[cosα(1+cosα)+sin²α]/[sinα(1+cosα)]==[cosα+cos²α+sin²α] / [sinα(1+cosα)] = [cosα+1] / [sinα(1+cosα)]=
=1/sinα