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1GromZadira
@1GromZadira
June 2021
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(1/1+ctg^2альфа+cos^2альфа)*tg^2альфа
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Nargiza9501
(1/1+ctg^2alfa+cos^2alfa)×tg^2alfa=(1/1/sin^2alfa+cos^2alfa)×tg^2alfa=(sin^2alfa+cos^2alfa)×tg^2alfa=1×tg^2alfa=tg^2alfa
Ответ:tg^2alfa
2 votes
Thanks 1
1GromZadira
огромное спасибо!
Nargiza9501
Не за что)) рада что помогла
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Ответ:tg^2alfa