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hitrtanya1
@hitrtanya1
October 2021
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упростите выражение:
1/(1+ctg²альфа) + cos²альфа
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Answers & Comments
sukonnikoffma
Ctg^2(l)=cos^2(l)/sin^2(l)
1+ctg^2(l)= (sin^2(l)+cos^2(l))/sin^2(l)=1/sin^2(l)
1/1/sin^2(l)=sin^2(l)
sin^(l)+cos^2(l)=1
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Thanks 1
hitrtanya1
а это что? (l)
sukonnikoffma
альфа
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Answers & Comments
1+ctg^2(l)= (sin^2(l)+cos^2(l))/sin^2(l)=1/sin^2(l)
1/1/sin^2(l)=sin^2(l)
sin^(l)+cos^2(l)=1