Вычислить предел (2x^2-3x-5)/(1+х+3х^2), если x стремится к ∞. Created by QiRong. algebra-ru

(1+х+3х^2), если x стремится к ∞...

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August 2021 1 6 Report

Вычислить предел (2x^2-3x-5)/(1+х+3х^2), если x стремится к ∞

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Ответ:

$\lim\limits _{x \to \infty}\dfrac{2x^2-3x-5}{1+x+3x^2}=\lim\limits _{x \to \infty}\dfrac{2-\frac{3}{x}-\frac{5}{x^2}}{\frac{1}{x^2}+\frac{1}{x}+3}=\dfrac{2-0-0}{0+0+3}=\dfrac{2}{3}$

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Verified answer

ispravte oshibki v tekste olardy oamday les salmay 60 65 tmenge tam ura

1cos2a0acd13e104298d847c8078200100d462 29282

vstavte podhodyashie po smyslu slova v predlozheniya fill in the correct word face

sostavte shemu odnorodnyh chlenov predlozheniya konechno zhe drevnyaya istoriya arhe

Use the verbs in the present indefinite tense:1) wealth (to consist) of goods ha...

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