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imworld
@imworld
August 2022
2
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1) log9x+2log3x=5
9 і 3 основа
2)
log2(x^2-3)+1=log2(6x-10)
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uekmyfhfp
Ответ смотри во вложении
3 votes
Thanks 6
NNNLLL54
Verified answer
2) log2_(x^2-3) +log2_2=log2_(6x-10)
log2_(2x^2-6)=log2_(6x-10)
2x^2-6=6x-10
2x^2-6x+4=0
x^2-3x+2=0 x1=1 x2=2
Сравним с одз x^2>3
6x-10>0
x=1 не является корнем Ответ х=2
5 votes
Thanks 6
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Answers & Comments
Verified answer
2) log2_(x^2-3) +log2_2=log2_(6x-10)log2_(2x^2-6)=log2_(6x-10)
2x^2-6=6x-10
2x^2-6x+4=0
x^2-3x+2=0 x1=1 x2=2
Сравним с одз x^2>3
6x-10>0
x=1 не является корнем Ответ х=2