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сашанун75
@сашанун75
November 2021
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1.(n-6)(2n+3)-(n-7)в квадрате-(2+n)(n-2)
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tan4ik3107
(n-6)(2n+3)-(n-7)²-(2+n)(n-2)=
2n²-12n-18+3n-(n²-14n+49)-(n²-4)=
2n²-12n-18+3n-n²+14n-49-n²+4=
5n-63
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Answers & Comments
2n²-12n-18+3n-(n²-14n+49)-(n²-4)=
2n²-12n-18+3n-n²+14n-49-n²+4=
5n-63