July 2022 0 3 Report
1.Найдите корни уравнения,принадлежащие отрезку [0;2pi]:
(1+cos x)(√2sinx-1)=0
2.Решите уравнение:
tg x-2ctg x+1=0
3.Решите Уравнение:
3sin^2x-sinxcosx=2
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