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krsk16
@krsk16
July 2022
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1.найти множество значений функции у=3cos2x-4
2.решите уравнение 4cosx=2
3.решите уравнение 2sin^2x+sinx-1=0
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sedinalana
Verified answer
1
E(y)=3*[-1;1]-4=[-3;3]-4=[-7;-1]
2
cosx=1/2
x=+-π/3+2πk,k∈z
3
sinx=a
2a²-a-1=0
D=1+8=9
a1=(1+3)/4=1⇒sinx=1⇒x=π/2+2πk,k∈z
a2=(1-3)/4=-1/2⇒sinx=-1/2⇒x=(-1)^(k+1)*π/6+πk,k∈z
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Answers & Comments
Verified answer
1E(y)=3*[-1;1]-4=[-3;3]-4=[-7;-1]
2
cosx=1/2
x=+-π/3+2πk,k∈z
3
sinx=a
2a²-a-1=0
D=1+8=9
a1=(1+3)/4=1⇒sinx=1⇒x=π/2+2πk,k∈z
a2=(1-3)/4=-1/2⇒sinx=-1/2⇒x=(-1)^(k+1)*π/6+πk,k∈z