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evlisu
@evlisu
November 2021
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1.напишите уравнение касательной к графику функции f(x)=ln(2x+2) в точке =- 2. найдите производную функции:а)y=x^7+2x^5-3x^4+8-0.12x; б)y=x^2sinx+3lnx+6e^x+4; в)y=+1g6^x^2; г)y=*+*.
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