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Ванесса1212
@Ванесса1212
July 2022
1
4
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1)sin7°cos23°+sin23°cos7°+3=?
2)sin60°cos26°+cos64°sin26°-sin30°=?
3)8sin25°sin65°деленное дробной чертой на cos40°=?
4)tg12°+tg33° деленное дробной чертой на 1-tg12°tg33°
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oganesbagoyan
Verified answer
1)
...=sin(7°+23°) +3 = sin30°+3=
3,5 ;
2)
... = sin( 64°+ 26°)- 1/2 =sin90° -1/2= 1-1/2
=1/2 ;
3)
...
= 8sin25°*sin(90° -25°)/cos40° =8sin25°*cos25° /cos40° =4sin50 °/cos40° =
=4sin(90°-40°)/cos40° =4cos40°/cos40°
=4
;
4) ...
=
(tq12°+tq33)°/(1-tq12°*tq33° =tq(12°+33°) =tq45°
=1 .
4 votes
Thanks 4
Ванесса1212
Спасибо большое!))
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Verified answer
1) ...=sin(7°+23°) +3 = sin30°+3= 3,5 ;2) ... = sin( 64°+ 26°)- 1/2 =sin90° -1/2= 1-1/2 =1/2 ;
3) ...= 8sin25°*sin(90° -25°)/cos40° =8sin25°*cos25° /cos40° =4sin50 °/cos40° =
=4sin(90°-40°)/cos40° =4cos40°/cos40° =4 ;
4) ...= (tq12°+tq33)°/(1-tq12°*tq33° =tq(12°+33°) =tq45° =1 .