1. 1) (x-2)(x-3)=x²-3x-2x+6=x²-5x+6
2) (2x²-y²)(3y²-x²)=6x²y²-2x⁴-3y⁴+x²y²
=7x²y²-2x⁴-3y⁴
3. 1)2-(x-1)(x+1)=2-(-3-1)(-3+1)=2-(-4)(-2)=
2-8=-6
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Answers & Comments
1. 1) (x-2)(x-3)=x²-3x-2x+6=x²-5x+6
2) (2x²-y²)(3y²-x²)=6x²y²-2x⁴-3y⁴+x²y²
=7x²y²-2x⁴-3y⁴
3. 1)2-(x-1)(x+1)=2-(-3-1)(-3+1)=2-(-4)(-2)=
2-8=-6