1)(x+2)(x-2)-(x+2)^22)(a-2)(a-6)-(a-4)^23) 1 1 ____

July 2022 1 8 Report

1)(x+2)(x-2)-(x+2)^2

2)(a-2)(a-6)-(a-4)^2

3) 1 1
____ - ____
3x+y 3x-y

4) m(m+2) m+2
________ - _________
m^3-8 m^2 2m+4

5) x x
(___ - ___ )=6
5 2

6)график функции y=ax^2 проходит через точку А(2;-8) найдите значение а

7)график функции y=ax^4 проходит через точку А(-2;16) найдите значение а

Answers & Comments

Artem112

Verified answer

(x+2)(x-2)-(x+2)^2=x^2-4-x^2-4x-4=-4x-8

(a-2)(a-6)-(a-4)^2=a^2-8a+12-a^2+8a-16=-4

$\frac{1}{3x+y} - \frac{1}{3x-y} =
 \frac{3x-y-3x-y}{9x^2-y^2} = \frac{-2y}{9x^2-y^2}$

$\frac{m(m+2)}{m^3-8}- \frac{m+2}{m^2-2m+4} =
 \frac{m(m+2)}{m^3-8}- \frac{(m+2)(m+2)}{m+2)(m^2-2m+4)} =
\\\
= \frac{m^2+2m-m^2-4m-m^2}{m^3-8}= \frac{-m(2-m)}{(m-2)(m^2+2m+4)}=
\\\
= \frac{m}{m^2+2m+4}$

$\frac{x}{5} - \frac{x}{2} =6
2x-5x=60
\\\
-3x=60
\\\
x=-20$

$y=ax^2
\\\
-8=2^2a
\\\
-8=4a
\\\
a=-2$

$y=ax^4
\\\
16=(-2)^4a
\\\
16=16a
\\\
a=1$

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Answers & Comments

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