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jungkooklove97
@jungkooklove97
July 2022
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Помогите:∫(2/0) x^2dx=.....
∫(4/1)x^3dx=....
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Lector55
1) ∫(2/0) x^2dx=x³/3 |(2/0)=(2³/3)-(0³/3)=8/3
2) ∫(4/1) x^3dx=x⁴/4 |(4/1)=(4⁴/4)-(1⁴/4)=(256/4)-(1/4)=255/4
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moboqe
аааа, это пределы интегрирования такие
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Answers & Comments
2) ∫(4/1) x^3dx=x⁴/4 |(4/1)=(4⁴/4)-(1⁴/4)=(256/4)-(1/4)=255/4