Ответ:
1) 10a+(4−4a)= (s−5d)−(−d+5s)
10a+4−4a= s−5d−(−d+5s)
6a+4. s−5d+d−5s
−4s−5d+d
-4s-4d
2) −(46−10)+(4−56) −(5n+m)+(−4n+8m)−(2m−5n)
−36+(4−56) −(5n+m)−4n+8m−(2m−5n)
−36−52 −5n−m−4n+8m−(2m−5n)
-88 −9n+7m−(2m−5n)
−9n+7m−2m+5n
−4n+7m−2m
−4n+5m
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Answers & Comments
Ответ:
1) 10a+(4−4a)= (s−5d)−(−d+5s)
10a+4−4a= s−5d−(−d+5s)
6a+4. s−5d+d−5s
−4s−5d+d
-4s-4d
2) −(46−10)+(4−56) −(5n+m)+(−4n+8m)−(2m−5n)
−36+(4−56) −(5n+m)−4n+8m−(2m−5n)
−36−52 −5n−m−4n+8m−(2m−5n)
-88 −9n+7m−(2m−5n)
−9n+7m−2m+5n
−4n+7m−2m
−4n+5m