1.Координаты вектора n = 3a - 2b равны:

n = 3(2, 1, -4) - 2(3, 0, -4) = (6, 3, -12) - (6, 0, -8) = (0, 3, -4)

2.Длина вектора n равна:

|n| = √(0^2 + 3^2 + (-4)^2) = √25 = 5.

Verified answer

Ответ:

n= (3•2;3•1;3•(-4)) - (2•3;2•0;2•(-4))=

n= (6;3;-12) - (6;0;-8) = (6-6;3-0;-12-(-8))

n= (0;3;-4)

2) Модуль =

[tex] \sqrt{3 {}^{2} + ( - 4) {}^{2} = } \sqrt{25} = 5[/tex]