Ответ:
Объяснение:
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[tex]y = {x}^{2} +1 2x - 4 \\ y' = 2x + 12 \\ 2x + 12 = 0 \\ 2x = - 12 \\ x = - 12 \div 2 \\ x = - 6 \\ - - - - - [ - 6] + + + + + \\ x_{min} = - 6 \\ y_{min} = ( - 6) {}^{2} + 12 \times (- 6) - 4 = 36 - 72 - 4 = \\ = 36 - 76 = - 40[/tex]
Ответ: х = - 6 ; у = - 40
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Ответ:
Объяснение:
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Verified answer
[tex]y = {x}^{2} +1 2x - 4 \\ y' = 2x + 12 \\ 2x + 12 = 0 \\ 2x = - 12 \\ x = - 12 \div 2 \\ x = - 6 \\ - - - - - [ - 6] + + + + + \\ x_{min} = - 6 \\ y_{min} = ( - 6) {}^{2} + 12 \times (- 6) - 4 = 36 - 72 - 4 = \\ = 36 - 76 = - 40[/tex]
Ответ: х = - 6 ; у = - 40