Verified answer

Ответ:

[tex]\dfrac{x-3}{x^{2}-5x}; \quad -\dfrac{13}{150};[/tex]

Объяснение:

[tex]\dfrac{x^{2}+2x-15}{x^{3}+8x-33x}=\dfrac{x^{2}-3x+5x-15}{x^{3}-25x}=\dfrac{x(x-3)+5(x-3)}{x(x^{2}-25)}=\dfrac{(x-3)(x+5)}{x(x^{2}-5^{2})}=[/tex]

[tex]=\dfrac{(x-3)(x+5)}{x(x-5)(x+5)}=\dfrac{x-3}{x(x-5)}=\dfrac{x-3}{x^{2}-5x};[/tex]

[tex]x=-10; \quad \dfrac{-10-3}{(-10)^{2}-5 \cdot (-10)}=\dfrac{-(10+3)}{100+50}=-\dfrac{13}{150};[/tex]