1. 4 cos^2x+12sinx+3=0
2. (sin x/2 - 1)(ctgx+√3)=0
1)
sin x=3,5 или
реш.нет
Ответ
2)
или
x=П+4Пn
Ответ П+4Пn;
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Answers & Comments
1)
sin x=3,5 или![sinx=-1/2 sinx=-1/2](https://tex.z-dn.net/?f=sinx%3D-1%2F2)
реш.нет![x= (-1)^{k+1}\frac{\pi}{6}+\pi*k x= (-1)^{k+1}\frac{\pi}{6}+\pi*k](https://tex.z-dn.net/?f=x%3D%20%28-1%29%5E%7Bk%2B1%7D%5Cfrac%7B%5Cpi%7D%7B6%7D%2B%5Cpi%2Ak)
Ответ![x= (-1)^{k+1}\frac{\pi}{6}+\pi*k x= (-1)^{k+1}\frac{\pi}{6}+\pi*k](https://tex.z-dn.net/?f=x%3D%20%28-1%29%5E%7Bk%2B1%7D%5Cfrac%7B%5Cpi%7D%7B6%7D%2B%5Cpi%2Ak)
2)
x=П+4Пn
Ответ П+4Пn;![\frac{5\pi}{6}+\pi m \frac{5\pi}{6}+\pi m](https://tex.z-dn.net/?f=%5Cfrac%7B5%5Cpi%7D%7B6%7D%2B%5Cpi%20m)