[tex]\displaystyle\bf\\c^{2} \cdot(c-2)-10c\cdot(c-2)+25\cdot(c-2)=\\\\\\=(c-2)\cdot(c^{2} -10c+25)=(c-2)(c-5)^{2} \\\\\\(c-2)(c-5)^{2} =(c-2)(c-5)^{2}[/tex]
Что и требовалось доказать
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[tex]\displaystyle\bf\\c^{2} \cdot(c-2)-10c\cdot(c-2)+25\cdot(c-2)=\\\\\\=(c-2)\cdot(c^{2} -10c+25)=(c-2)(c-5)^{2} \\\\\\(c-2)(c-5)^{2} =(c-2)(c-5)^{2}[/tex]
Что и требовалось доказать