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Pestra
@Pestra
September 2021
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1. lg(2x)>lg(x/2)
2. 4sinacosa - sin2a
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sedinalana
Verified answer
ОДЗ x>0
2x>0,5x
2x-0,5x>0
1,5x>0
x>0
x∈(0;∞)
2sin2a-sin2a=sin2a
2 votes
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Answers & Comments
Verified answer
ОДЗ x>02x>0,5x
2x-0,5x>0
1,5x>0
x>0
x∈(0;∞)
2sin2a-sin2a=sin2a