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mironovayarosl1
@mironovayarosl1
July 2022
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tgx+cos(3π/2 -2x)=0
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Ilyasssssss
Tgx-sin2x=0
sinx(1/cosx-2cosx)=0
1)sinx=0⇒x=π+πn
2)cos2x=0⇒2x=π/2+πn⇒x=π/4+πn/2
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Answers & Comments
sinx(1/cosx-2cosx)=0
1)sinx=0⇒x=π+πn
2)cos2x=0⇒2x=π/2+πn⇒x=π/4+πn/2