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anadomovaa77
@anadomovaa77
October 2021
2
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2 – 3х > 3х + 1
3 – х ≤ 4 + 6х
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slavuta1333
ОТВЕТ
1
.
2
.
Пошаговое объяснение:
1
.
2
.
2 votes
Thanks 0
dprssun
1) 2 - 3x > 3x + 1
3x + 3x < 2 - 1
6x < 1
x < 1/6
2) 3 - x <= 4 + 6x
6x + x => 3 - 4
7x => - 1
x => - 1/7
Ответ: 1) (- бесконечности; 1/6); 2) [- 1/7; + бесконечности).
0 votes
Thanks 0
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Answers & Comments
ОТВЕТ
1.
2.
Пошаговое объяснение:
1.
2.
3x + 3x < 2 - 1
6x < 1
x < 1/6
2) 3 - x <= 4 + 6x
6x + x => 3 - 4
7x => - 1
x => - 1/7
Ответ: 1) (- бесконечности; 1/6); 2) [- 1/7; + бесконечности).