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elimin
@elimin
August 2022
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Решите интеграл от 4 до 1 (х^2/2-3х^3-3)dx
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ПрофиЗнания
( x^3/6 - 3x^4/4 -3x) |(1;4) = 4^3/6 -3*4^4/4 -3*4 - 1/6+3/4+3 =
=64/6 - 3*64-12-1/6+3/4+3= 63/6-192-12+0,75+3=-201+10,5+0,75=-201+11,25=-189,75
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Answers & Comments
=64/6 - 3*64-12-1/6+3/4+3= 63/6-192-12+0,75+3=-201+10,5+0,75=-201+11,25=-189,75