a)√2*cosx+1 _________ =0 √17sinx б) x ∈ {3п/2 ; 3п}. Created by hatermur. algebra-ru

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August 2022 1 4 Report

a)√2*cosx+1
_________ =0
√17sinx
б) x ∈ {3п/2 ; 3п}

Answers & Comments

erzhan9210 Знаменатель не равен нулю, тогда
√2cosx+1=0
cosx=-1/√2=-√2/2
x=-45°и -135°

3π/2=270°
3π=540°
-45°+360°=315°
-135°+360°=225°
225°+360°=585°
ответ 315°

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