cos(3pi/2 + 3x) + 3sin3x - корень из 3 > 0. Created by zhyrgenbekov. algebra-ru

2 + 3x) + 3sin3x - корень из 3

zhyrgenbekov @zhyrgenbekov

September 2021 1 9 Report

cos(3pi/2 + 3x) + 3sin3x - корень из 3 > 0

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kirichekov

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Cos(3π/2+3x)+3sin3x-√3>0
sin3x+3sin3x-√3>0
4sin3x>√3, sin3x>√3/4
(-1)^n *arcsin(√3/4)+2πn<3x<(π-(-1)^n *arcsin(√3/4)+2πn), n∈Z |:3
x∈( ((-1)^n*arcsin(√3/4)+2πn)/3; (π-(1)^n*arcsin(√3/4)+2πn)/3 ), n∈Z

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