Объяснение:

[tex]3x ^{2} - 4x - 2 = 0 \\ 3x ^{2} - 4x = 2 \\ {x}^{2} - \frac{4}{3}x = \frac{2}{3} \\ {x}^{2} - \frac{4}{3}x + ... = \frac{2}{3} + ... \\ {x}^{2} - \frac{4}{3}x + \frac{4}{9} = \frac{2}{3} + ... \\ {x}^{2} - \frac{4}{3}x + \frac{4}{9} = \frac{2}{3} + \frac{4}{9} \\ (x - \frac{2}{3} )^{2} = \frac{10}{9} \\ x = \frac{ - \sqrt{10} + 2 }{ 3} \\ x = \frac{ \sqrt{10} + 2 }{3} \\ x1 = \frac{ - \sqrt{10} + 2}{3} \\ x2 = \frac{ \sqrt{10} + 2}{3} [/tex]