[tex]\displaystyle\bf\\\frac{18x^{2} -48xy+32y^{2} }{9x-12y} =\frac{2\cdot(9x^{2} -24xy+16y^{2} )}{3\cdot(3x-4y)} =\frac{2\cdot(3x-4y)^{2} }{3\cdot(3x-4y)} =\\\\\\=\frac{2\cdot(3x-4y)}{3} =-\frac{2\cdot(4y-3x)}{3} =-\frac{2\cdot(-0,2)}{3} =\frac{2}{15}[/tex]