2-⁶·4-³ _____ 8-⁷·2⁰ Решите пожалуйста. Created by alisher2008w. algebra-ru

2-⁶·4-³ _____ 8-⁷·2⁰ Решите пожалуйста...

alisher2008w @alisher2008w

July 2022 1 11 Report

2-⁶·4-³
_____
8-⁷·2⁰
Решите пожалуйста

Answers & Comments

sergeevaolga5

Ответ:

512

Объяснение:

$\frac{2^{-6}*4^{-3}}{8^{-7}*2^0}=\frac{2^{-6}*(2^2)^{-3}}{(2^3)^{-7}*1}=\frac{2^{-6}*2^{-6}}{2^{-21}}=\frac{2^{-12}}{2^{-21}}=2^{-12-(-21)}=\\\\=2^{-12+21}=2^9=512$

***

$a^n*a^m=a^{n+m}\\\\(a^n)^m=a^{nm}\\\\\frac{a^n}{a^m}=a^{n-m}$

$a^0=1$

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