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luna1616
@luna1616
July 2022
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Решите пожалуйста: f(x)=3x^2-x/2-5. F(-2)=5, найдите F(-1).
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nafanya2014
Verified answer
F(x)=x³-(x²/4)-5x+C
F(-2)=(-2)³-((-2)²/4)-5·(-2)+C
5=(-2)³-((-2)²/4)-5·(-2)+C ⇒ C=4
Значит,
F(x)=x³-(x²/4)-5x+4
F(-1)=-1-(1/4)+5+4
F(-1)=7,75
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Answers & Comments
Verified answer
F(x)=x³-(x²/4)-5x+CF(-2)=(-2)³-((-2)²/4)-5·(-2)+C
5=(-2)³-((-2)²/4)-5·(-2)+C ⇒ C=4
Значит,
F(x)=x³-(x²/4)-5x+4
F(-1)=-1-(1/4)+5+4
F(-1)=7,75