[tex]-x^{2} +6x=8\\x^{2} -6x+8=0\\ (x-2)(x-4)=0\\D=6^{2} -8*4=4=2^{2} \\x_{1} =\frac{6+2}{2} =4\\x_{2} =\frac{6-2}{2} =2\\[/tex]
Ответ:{4,2}
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[tex]-x^{2} +6x=8\\x^{2} -6x+8=0\\ (x-2)(x-4)=0\\D=6^{2} -8*4=4=2^{2} \\x_{1} =\frac{6+2}{2} =4\\x_{2} =\frac{6-2}{2} =2\\[/tex]
Ответ:{4,2}