2.
[tex](x+3)(x-8)=0\\x^2+3x-8x-24=0\\x^2-5x-24=0[/tex]
3.
[tex]x^2-x = 2x+4\\x^2-x-2x-4=0\\x^2-3x-4=0\\x1 = \frac{3+\sqrt{9+16}}{2} = 4\\x2 = \frac{3-\sqrt{9+16}}{2} = -1\\[/tex]
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Answers & Comments
2.
[tex](x+3)(x-8)=0\\x^2+3x-8x-24=0\\x^2-5x-24=0[/tex]
3.
[tex]x^2-x = 2x+4\\x^2-x-2x-4=0\\x^2-3x-4=0\\x1 = \frac{3+\sqrt{9+16}}{2} = 4\\x2 = \frac{3-\sqrt{9+16}}{2} = -1\\[/tex]