[tex]\displaystyle 6\frac{3}{17}:(\frac{7}{17}-1)-4*4\frac{1}{2}=\frac{105}{17}:(-\frac{10}{17})-4*\frac{9}{2}=-\frac{105}{17}*\frac{17}{10}-2*9=-21*\frac{1}{2}-18=\\\\-\frac{21}{2}-18=-\frac{57}{2}=-28\frac{1}{2}=-28,5[/tex]
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[tex]\displaystyle 6\frac{3}{17}:(\frac{7}{17}-1)-4*4\frac{1}{2}=\frac{105}{17}:(-\frac{10}{17})-4*\frac{9}{2}=-\frac{105}{17}*\frac{17}{10}-2*9=-21*\frac{1}{2}-18=\\\\-\frac{21}{2}-18=-\frac{57}{2}=-28\frac{1}{2}=-28,5[/tex]