Ответ:

Пользуемся формулами    [tex](a\pm b)^2=a^2\pm 2ab+b^2[/tex]  .

[tex]1)\ \ (19-2x)^2=19^2-2\cdot 19\cdot 2x+(2x)^2=361-76x+4x^2\\\\(3m+4)^2=9m^2+24m+16\\\\(7b-2c)=49b^2-28bc+4c^2\\\\(d+3x)^2=d^2+6dx+9x^2\\\\(15c-0,5d)^2==225c^2-15cd+0,25d^2\\\\(10c+5x)^2=100c^2+100cx+25x^2[/tex]

[tex]2)\ \ (9c+*)^2=81c^2+25+80c=(9c+5)^2\\\\(*+3y^3)^2=9y^6+60y^3+100=(10+3y^3)^2\\\\(17c^2-2x)^2=*\ +4x^2+289c^4=68c^2x+4x^2+289c^4\\\\(10m^2-0,6m^4)=100m^4+\ *\ -12m^6=100m^4+0,36m^8-12m^6[/tex]