[tex]\displaystyle 1)12\frac{1}{9}+4\frac{2}{5}-5+7\frac{3}{5}=12+\frac{1}{9}+4+\frac{2}{5}-5+7+\frac{3}{5}=(12+4-5+7)+(\frac{1}{9}+\frac{2}{5}+\frac{3}{5})=\\\\18+\frac{10}{9}=18+1\frac{1}{9}=18+1+\frac{1}{9}=19+\frac{1}{9}=19\frac{1}{9}=\frac{172}{9}\\ \\2)6\frac{3}{8}-2\frac{1}{3}+\frac{1}{8}+2\frac{1}{2}=\frac{51}{8}-\frac{7}{3}+\frac{1}{8}+\frac{5}{2}=\frac{20}{3}=6\frac{2}{3}[/tex]