[tex]\displaystyle\bf\\f(x)=5x-1\\\\g(x)=\frac{x+1}{5}=0,2x+0,2\\\\\\f\Big(g(x)\Big)=5\cdot(0,2x+0,2)-1=x+1-1=x\\\\\boxed {f^{2} \Big(g(x)\Big) =x^{2} }\\\\\\g\Big(f(x)\Big)=0,2\cdot(5x-1)+0,2=x-0,2+0,2=x\\\\\boxed{g^{2} \Big(f(x)\Big)=x^{2}}\\\\\\f^{2} \Big(g(x)\Big)- g^{2} \Big(f(x)\Big)=x^{2} -x^{2} =0\\\\\\Otvet \ : \ A=0[/tex]
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
[tex]\displaystyle\bf\\f(x)=5x-1\\\\g(x)=\frac{x+1}{5}=0,2x+0,2\\\\\\f\Big(g(x)\Big)=5\cdot(0,2x+0,2)-1=x+1-1=x\\\\\boxed {f^{2} \Big(g(x)\Big) =x^{2} }\\\\\\g\Big(f(x)\Big)=0,2\cdot(5x-1)+0,2=x-0,2+0,2=x\\\\\boxed{g^{2} \Big(f(x)\Big)=x^{2}}\\\\\\f^{2} \Big(g(x)\Big)- g^{2} \Big(f(x)\Big)=x^{2} -x^{2} =0\\\\\\Otvet \ : \ A=0[/tex]