[tex]\displaystyle\bf\\12 \ arcCos\frac{\sqrt{3} }{2} =12\cdot\frac{\pi }{6}=2\pi[/tex]
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[tex]\displaystyle\bf\\12 \ arcCos\frac{\sqrt{3} }{2} =12\cdot\frac{\pi }{6}=2\pi[/tex]