Ответ:
[tex] \frac{5}{a} + \frac{a - 5}{a + 2} = ...[/tex]
а≠0, а≠-2
[tex]5(a + 2) + a(a - 5) = \\ = 5a + 10 + {a}^{2} - 5a = \\ = {a}^{2} + 10 [/tex]
[tex]... = \frac{ {a}^{2} + 10 }{a(a + 2)} [/tex]
[tex] \frac{2 {x}^{2} }{ {x}^{2} - 4 } - \frac{2x}{x + 2} = ...[/tex]
х≠±2
[tex]2 {x}^{2} - 2x(x - 2) = 2 {x}^{2} - 2 {x}^{2} + 4x = 4x[/tex]
[tex]... = \frac{4x}{ {x}^{2} - 4 } [/tex]
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Answers & Comments
Ответ:
[tex] \frac{5}{a} + \frac{a - 5}{a + 2} = ...[/tex]
а≠0, а≠-2
[tex]5(a + 2) + a(a - 5) = \\ = 5a + 10 + {a}^{2} - 5a = \\ = {a}^{2} + 10 [/tex]
[tex]... = \frac{ {a}^{2} + 10 }{a(a + 2)} [/tex]
[tex] \frac{2 {x}^{2} }{ {x}^{2} - 4 } - \frac{2x}{x + 2} = ...[/tex]
х≠±2
[tex]2 {x}^{2} - 2x(x - 2) = 2 {x}^{2} - 2 {x}^{2} + 4x = 4x[/tex]
[tex]... = \frac{4x}{ {x}^{2} - 4 } [/tex]