(2cos(a-2pi)-sin(a-pi/2)):(cos(9pi/2-a)+2sin(2pi-a))упростить, пожалуйста.. Created by alyonaimran. algebra-ru

2-a)+2sin(2pi-a))упростить, пожалуйста...

August 2022 1 0 Report

(2cos(a-2pi)-sin(a-pi/2)):(cos(9pi/2-a)+2sin(2pi-a))
упростить, пожалуйста.

Answers & Comments

zarembo73 (2cos(a-2π)-sin(a-π/2))/(cos(9π/2-a)+2sin(2π-a))=
=(2cos(2π-a)+sin(π/2-a))/(cos(9π/2-a)+2sin(2π-a))=
=(2cosα+cosα)/(cos(4π+(π/2-α))-2sinα=3cosα/(cos(π/2-α)-2sinα)=
=3cosα/(sinα-2sinα)=3cosα/-sinα=-3ctgα.

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sredi chisel 263273657456729 vyberite chislov kotorom cifra 7 zapisana v razryad

chsostavit uravnenie s pomoshyu kotorogo mozhno najti skorost x techeniya reki

najdite naimenshee naturalnoe chislobolshee 11kotoroe pri delenii na 13na 21b710fe81ec75a293cbfb021c105d55d2 30067

najdite kolichestvo kornej uravneniya sin6x sin3x0 na promezhutke 10080 s

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