упростите выражение 3sin(pi-α)*cos(pi/2-α)+3sin^2(pi/2-α). Created by kris2413. algebra-ru

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kris2413 @kris2413

September 2021 1 6 Report

упростите выражение 3sin(pi-α)*cos(pi/2-α)+3sin^2(pi/2-α)

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Freakazoid

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$\displaystyle
3sin(\pi- \alpha )*cos(\frac{\pi}{2}- \alpha )+3sin^2(\frac{\pi}{2}- \alpha )=\\ 
3sin \alpha *sin \alpha +3cos^2 \alpha =3sin^2 \alpha +3cos^2 \alpha =\\ 3(sin^2 \alpha +cos^2 \alpha )=3$

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2a tg2pi a

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2a tg2pi a

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