помогите пожалуйста упростить(решить)
2tg(π-α)/cos(π-α)+sin(-α)
1+(sinα-cosα)+sin²(3π/2-α)
2tg(π-α)/cos(π-α)+sin(-α)
1+(sinα-cosα)+sin²(3π/2-α)
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Answers & Comments
2tg(π-α)/cos(π-α)+sin(-α) = (-2tgα) / (cosα) - sinα = - (sinα*(2 + cos^2x) / cos^2x
1+(sinα-cosα)+sin²(3π/2-α) = 1 +sinα - cosα + cos^2α = 2co^2α + sinα - cosα