Доведи тотожності:
а) 2(а – b – 1) – (a + b – 1) – (a – b + 1) = –2(b + 1);
б) 1 – х – (1 – (1 – (1 – х))) = 0.
а) 2(а – b – 1) – (a + b – 1) – (a – b + 1) = –2(b + 1);
б) 1 – х – (1 – (1 – (1 – х))) = 0.
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Ответ:
Объяснение:
а) 2(а – b – 1) – (a + b – 1) – (a – b + 1) = 2а-2b-2-a-b+1-a+b-1=-2b+2=-2(b+1)
–2(b + 1)=–2(b + 1).
б) 1 – х – (1 – (1 – (1 – х))) =
1-х-1+1-1+х=0.
0=0.
Ответ:
Объяснение:
а) 2(а – b – 1) – (a + b – 1) – (a – b + 1) = –2(b + 1);
2а -2b -2 - a - b +1 -a +b -1= -2b -2
2a -a -a -2b -b+b -2 +1-1 = - 2b -2
-2b -2= - 2b -2
б) 1 – х – (1 – (1 – (1 – х))) = 0.
1 -х - (1 -(1 -1+х))=0
1 - х - (1 - х)=0
1 - х - 1 +х=0
1-1 -х+х=0
0=0