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SnowWhite98
@SnowWhite98
December 2021
2
6
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Алгебра упростить выражение
а-альфа, b-бетта.
cos(п/2-ą)*sin(п/2-b)-sin(a-b)
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Answers & Comments
crdd
Verified answer
Cos(Π/2-a) * sin(Π/2-b) - sin(a-b) = sina * cosb -(sina*cosb-cosa*sinb) = sina * cosb -sina*cosb+cosa*sinb = cosa*sinb
0 votes
Thanks 1
oganesbagoyan
Verified answer
Упростить выражение
cos(
π/2-α)*sin(π/2-β
) - sin(
α-β
)
--------------
cos(π/2-α)*sin(π/2-β) - sin(α-β) =sinα*cosβ -(sinα*cosβ -cosα*sinβ) =cosα*sin
β.
* * *
использован
ы
формулы приведения :
cos(π/2 - α) = sinα ;
sin(π/2 - β) =cosβ.
1 votes
Thanks 1
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Answers & Comments
Verified answer
Cos(Π/2-a) * sin(Π/2-b) - sin(a-b) = sina * cosb -(sina*cosb-cosa*sinb) = sina * cosb -sina*cosb+cosa*sinb = cosa*sinbVerified answer
Упростить выражениеcos(π/2-α)*sin(π/2-β) - sin(α-β)
--------------
cos(π/2-α)*sin(π/2-β) - sin(α-β) =sinα*cosβ -(sinα*cosβ -cosα*sinβ) =cosα*sinβ.
* * *
использованы формулы приведения :
cos(π/2 - α) = sinα ;
sin(π/2 - β) =cosβ.