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anya9797
@anya9797
July 2022
2
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sin(2x-[tex]\pi /3)[/tex] <1/2
Через окружность надо решить! Пожалуйста
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Алкадиеныч
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Решение на фотографии
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KuOV
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- 7π/6 + 2πn < 2x - π/3 < π/6 + 2πn
- 5π/6 + 2πn < 2x < π/2 + 2πn
- 5π/12 + πn < x < π/4 + πn
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Решение на фотографииVerified answer
- 7π/6 + 2πn < 2x - π/3 < π/6 + 2πn- 5π/6 + 2πn < 2x < π/2 + 2πn
- 5π/12 + πn < x < π/4 + πn